document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120869>Question 1120869</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the equation of line passing through A(-2,3) and perpendicular to the line 2x-3y+6=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #736553 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=736553\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Rewrite equation of line as 3y=2x+6 or y=(2/3)x+2<BR>\n" );
document.write( "perpendicular line has negative reciprocal slope or -3/2<BR>\n" );
document.write( "point-slope formula y-y1=m(x-x1) where m slope and (x1, y1) point<BR>\n" );
document.write( "y-3=(-3/2)(x+2)<BR>\n" );
document.write( "y-3=-(3/2)x-3<BR>\n" );
document.write( "y=-3/2 x<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );