document.write( "Question 1120861: A man travels from Town A to Town B at an average speed of 4 km and from Town B to Town A at an average speed of 6km. If he takes 45 mins to complete the entire journey, find the total distance traveled. \n" ); document.write( "
Algebra.Com's Answer #736550 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Since the distances are the same and the speeds for the two legs are in the ratio 2:3, the amounts of time required for the two legs are in the ratio 3:2. \n" ); document.write( "45 minutes divided in the ratio 3:2 means 27 minutes (9/20 hours) for the trip at 4km/hr and 18 minutes (3/10 hours) for the trip at 6km/hr. \n" ); document.write( "The distance between the towns is \n" ); document.write( "(4km/hr)(9/20hr) = 36/20km = 1.8km \n" ); document.write( "or \n" ); document.write( "(6km/hr)(3/10hr) = 18/10km = 1.8km \n" ); document.write( "The total distance is then 2(1.8km) = 3.6km. \n" ); document.write( " |