document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120744>Question 1120744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> discuss how you will find the sum of the series: \r<BR>\n" );
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document.write( "1/2 + 1/4 + 1/8+ ... + 1/512\r<BR>\n" );
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document.write( "* our topic focuses on harmonic and fibonacci sequence but it can be other types of sequences or series :-) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #736453 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=736453\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a geometric series is defined as<BR>\n" );
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document.write( "x(n) = a * r^(n-1), where x(n) is the nth term, r is the common ratio and a is the first term<BR>\n" );
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document.write( "for this problem a = 1/2 and r = 1/2<BR>\n" );
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document.write( "the sum of the first n terms of a geometric series is defined as<BR>\n" );
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document.write( "summation for k from 0 to n-1 of (ar^k) = a * (1 - r^n) / (1 -r) =<BR>\n" );
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document.write( "(1/2) * (1 -(1/2)^n) / (1 -(1/2)) =<BR>\n" );
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document.write( "(1/2) * (1 -(1/2)^n) * 2 = (1 -(1/2)^n) <BR>\n" );
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