document.write( "Question 1120729: Isabela has $2.55 in quarters,nickels and dimes. She has twice as many nickels as dimes and one less quarter than nickels. How many of each coin does she have? \n" ); document.write( "
Algebra.Com's Answer #736422 by greenestamps(13209)\"\" \"About 
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\n" ); document.write( "Presumably this is a problem from an algebra class, where you are supposed to provide a solution using formal algebra.

\n" ); document.write( "But don't underestimate the value of the brain exercise you get by working the problem informally using logical reasoning.

\n" ); document.write( "(1) Add one more quarter, so that now the numbers of nickels and quarters are the same; that makes the new total value $2.80.

\n" ); document.write( "(2) Now the numbers of quarters and nickels are both twice the number of dimes. So separate the coins into groups of 2 quarters, 2 nickels and 1 dime. The value of each group is then 50+10+10 = 70 cents.

\n" ); document.write( "(3) The new total value of the coins is $2.80; the value of each group of coins is 70 cents. That means the number of groups of coins is 280/70 = 4.

\n" ); document.write( "(4) So the total number of coins in the 4 groups is 8 quarters, 8 nickels, and 4 dimes.

\n" ); document.write( "(5) And last take away that \"extra\" quarter you added at the beginning. You have the final answer of the $2.55 being made up of 7 quarters, 4 dimes, and 8 nickels.
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