document.write( "Question 1120734: A motorist reduces his annual distance travel by x% when the price of petrol is increased by y%. Find the increase percent in his petrol bill. \n" ); document.write( "
Algebra.Com's Answer #736417 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "The distance traveled (and therefore presumably the amount of petrol used) is multiplied by a factor of (1-x/100); the price is multiplied by a factor of (1+y/100). The total cost of the petrol is

\n" ); document.write( "(1-x/100)(1+y/100) = 1+y/100-x/100-xy/10000

\n" ); document.write( "The change in the cost of the petrol is

\n" ); document.write( "y/100-x/100-xy/10000

\n" ); document.write( "Multiplying by 100 to get the change as a percentage, the percent change in the cost is y-x-xy/100.

\n" ); document.write( "Note we don't know whether that is an increase or a decrease in total cost.

\n" ); document.write( "Example 1:
\n" ); document.write( "Decrease travel by 10% when the price increases by 20% (x=10,y=20)
\n" ); document.write( "The distance traveled gets multiplied by (1-.10) = .90; the price gets multiplied by (1+.20) = 1.20
\n" ); document.write( "The total cost gets multiplied by (.90)(1.20) = 1.08, an increase of 8%
\n" ); document.write( "By the formula, 20-10-200/100 = 10-2 = 8 percent

\n" ); document.write( "Example 2:
\n" ); document.write( "Decrease travel by 30% when the cost increases by 10% (x=30, y=10)
\n" ); document.write( "The distance traveled gets multiplied by (1-.30) = .70; the price gets multiplied by (1+.10) = 1.10
\n" ); document.write( "The total cost gets multiplied by (.70)(1.10) = 0.77, an decrease of 23%
\n" ); document.write( "By the formula, 10-30-300/100 = -20-3 = -23 percent
\n" ); document.write( "
\n" );