document.write( "Question 1120738: Hi, I need some help with working out this motion problem, thanks!\r
\n" ); document.write( "\n" ); document.write( "\"Gertrude rows her boat 24 miles downstream in 4 hours. In order to make the return trip upstream in the same amount of time, the rate of the boat in still water was doubled. Find the rate of the current and the rate that Gertrude was rowing downstream.\"
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Algebra.Com's Answer #736402 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"s\" = the speed of the boat going downstream
\n" ); document.write( "\"+2s+\" = the speed going upstream
\n" ); document.write( "Let \"+c+\" = the speed of the current
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\n" ); document.write( "Equation for going downstream
\n" ); document.write( "(1) \"+24+=+%28+s+%2B+c+%29%2A4+\"
\n" ); document.write( "Equation for going upstream
\n" ); document.write( "(2) \"+24+=+%28+2s+-+c+%29%2A4+\"
\n" ); document.write( "——————————————-
\n" ); document.write( "(1) \"+s+%2B+c+=+6+\"
\n" ); document.write( "(2) \"+2s+-+c+=+6+\"
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\n" ); document.write( "Add the equations
\n" ); document.write( "\"+3s+=+12+\"
\n" ); document.write( "\"+s+=+4+\"
\n" ); document.write( "And
\n" ); document.write( "(1) \"+4+%2B+c+=+6+\"
\n" ); document.write( "(1) \"+c+=+2+\"
\n" ); document.write( "———————————-
\n" ); document.write( "The rate of the current was 2 mi/hr
\n" ); document.write( "She was rowing at a rate of 4 mi/hr going downstream\r
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