document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120678>Question 1120678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please Help me solve this question\r<BR>\n" );
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document.write( " A garrison has provisions for a certain number of days; after 10 days 1/5 of the men desert and it is found the provisions will last just as long  as before; how long was that? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #736344 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=736344\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let n be the number of men and x be the number of days<BR>\n" );
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document.write( "after 10 days, there are 4n/5 men<BR>\n" );
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document.write( "x/n is the potion of the provisions per man<BR>\n" );
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document.write( "x/n = (x-10)/(4n/5)<BR>\n" );
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document.write( "cross multiply the fractions<BR>\n" );
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document.write( "4nx/5 = nx -10n<BR>\n" );
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document.write( "multiply both sides of = by 5<BR>\n" );
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document.write( "4nx = 5nx -50n<BR>\n" );
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document.write( "nx = 50n<BR>\n" );
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document.write( "x = 50<BR>\n" );
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document.write( "the provisions last for 50 days<BR>\n" );
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