document.write( "Question 1120665: An airline flies between 2 major cities daily. It normally transports 81 people a day at a cost of $210 per person. The airline estimates that it will lose 2 passengers for every $6 that it increases the fare. What should the airline charge to gain the maximum income? \n" ); document.write( "
Algebra.Com's Answer #736340 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! It would be easier to use 1 passenger for every $3 raise. \n" ); document.write( "x=number of passengers changing \n" ); document.write( "(81-x)(210+3x)=17010+243x-210x-3x^2 \n" ); document.write( "This is -3x^2+33x+17010 \n" ); document.write( "x-value for maximum is at x=-b/2a or -33/6 or -5.50 \n" ); document.write( "This makes x 75.5, with a fare of $226.50, but we need integer number of passengers. Because this is not linear, we need to look at both sides of the decimal, at 75 and 76. \n" ); document.write( "76 passengers is the optimal number at a fare of $225 each.\r \n" ); document.write( "\n" ); document.write( "81---210 \n" ); document.write( "80---213 \n" ); document.write( "79---216 \n" ); document.write( "78---219 \n" ); document.write( "77---222=17094 \n" ); document.write( "76---225=17100 \n" ); document.write( "75---224=16800 \n" ); document.write( " \n" ); document.write( " |