document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120674>Question 1120674</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine the required value of the missing probability to make the distribution a discrete probability distribution.<BR>\n" );
document.write( "x        P(x)   <BR>\n" );
document.write( "3       0.27<BR>\n" );
document.write( "4       ?<BR>\n" );
document.write( "5       0.33<BR>\n" );
document.write( "6       0.21\r<BR>\n" );
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document.write( "P(4) =\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #736336 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=736336\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of each discrete probability must be 1, so since 0.81 is accounted for, the probability for x=4 has to be 0.19. </SPAN>\n" );
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