document.write( "Question 1120666: Factoring :
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document.write( "a)x^4+(x-4)^4-82
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document.write( "b)(x^2-a)^2-6x^2+4x+2a
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document.write( "Help me ! Thanks \n" );
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Algebra.Com's Answer #736333 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! One approach is to set the first to equal 0 \n" ); document.write( "x^4+(x-4)^4-82=0 \n" ); document.write( "x=3 can be see to be a solution \n" ); document.write( "x=1 can also be seen to be a solution \n" ); document.write( "This product of factors (x-3) and (x-1), or x^2-4x+3, can be divided into the expanded polynomial 2x^4-16x^3+96x^2-256x+174 \n" ); document.write( "or its equivalent of x^4-8x^3+48x^2-128x+87 \n" ); document.write( "to yield the quadratic x^2-4x+29, which is prime and the third factor of the original polyomial. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |