document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120597>Question 1120597</A>: <I><SPAN STYLE=\"word-break: break-all;\"> &#8203;38% of women consider themselves fans of professional baseball. You randomly select six women and ask each if she considers herself a fan of professional baseball. Complete parts&#8203; (a) through&#8203; (c) below.\r<BR>\n" );
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document.write( "&#8203;(a) Find the mean of the binomial distribution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #736293 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=736293\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The mean is np, where n here is 6 and p=0.38, so the mean or expected value is 2.28 women.<BR>\n" );
document.write( "The variance is np(1-p) or 2.28*62=1.41, and the sd is the sqrt of that, or 1.19 women. </SPAN>\n" );
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