document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120626>Question 1120626</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 11.	The distribution of annual earnings of all bank tellers with five years of experience is skewed negatively. This distribution has a mean of Birr 15,000 and a standard deviation of Birr 2000. If we draw a random sample of 30 tellers, what is the probability that their earnings will average more than Birr 15,750 annually? <BR>\n" );
document.write( "Required: <BR>\n" );
document.write( "•	Calculate µ and  <BR>\n" );
document.write( "•	Calculate Z for  <BR>\n" );
document.write( "•	Find the area covered by the interval<BR>\n" );
document.write( "•	Interpret the results<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #736290 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=736290\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z=(x bar-mean)/s/sqrt(n)<BR>\n" );
document.write( "z>(15750-15000)/2000/sqrt (30)<BR>\n" );
document.write( "z>750*sqrt(30)/2000<BR>\n" );
document.write( "z>2.05<BR>\n" );
document.write( "This probability is 0.0202<BR>\n" );
document.write( "The likelihood of a random sample of size 30 of having a mean of 15,750 or greater is just over 2%. </SPAN>\n" );
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