document.write( "Question 1120622: Dear Tutor
\n" ); document.write( "please help me with stats question\r
\n" ); document.write( "\n" ); document.write( "In a random sample of 200 observations,we found the proportion of successes to be 48%.
\n" ); document.write( "Use a 90% degree of confidence to estimate the population proportion of successes.
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Algebra.Com's Answer #736278 by Theo(13342)\"\" \"About 
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in a proportion type problem:\r
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\n" ); document.write( "\n" ); document.write( "p = the proportion of successes
\n" ); document.write( "q = the proportion of failures = 1 minus the proportion of successes
\n" ); document.write( "n = total number of observations = sample size\r
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\n" ); document.write( "\n" ); document.write( "the formulas to use are:\r
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\n" ); document.write( "\n" ); document.write( "p = .48 = proportion of successes
\n" ); document.write( "q = 1 - .48 = .52 = proportion of failures\r
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\n" ); document.write( "\n" ); document.write( "mean = p
\n" ); document.write( "standard error = sqrt(p*q/n)
\n" ); document.write( "z = (x-m)/s
\n" ); document.write( "x = raw score
\n" ); document.write( "m = raw mean
\n" ); document.write( "s = standard error\r
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\n" ); document.write( "\n" ); document.write( "90% degree of confidence results in a z-score of plus or minus 1.644853626 when using the TI-84 Plus scientific calculator.\r
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\n" ); document.write( "\n" ); document.write( "90% confidence interval results in an alpha o\r
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\n" ); document.write( "\n" ); document.write( "the alpha is the area under the normal distribution curve which is outside the confidence interval.\r
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\n" ); document.write( "\n" ); document.write( "look for the z-score that has an area of .05 to the left of it gives you the negative critical z-score.\r
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\n" ); document.write( "\n" ); document.write( "look for the z-score that has an area of .95 to the left of it gives you the positive critical z-score.\r
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\n" ); document.write( "\n" ); document.write( "a z-score that has an area of.95 to the left of it is the same as a z-score that has an area of .05 to the right of it.\r
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\n" ); document.write( "\n" ); document.write( "in your problem:\r
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\n" ); document.write( "\n" ); document.write( "m is the mean which is equal to p which is equal to .48
\n" ); document.write( "n is the sample size which is equal to 200\r
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\n" ); document.write( "\n" ); document.write( "s is the standard error which is equal to sqrt(p*q/n) which is equal to sqrt(.48*.52/200) which is equal to .0353270435\r
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\n" ); document.write( "\n" ); document.write( "critical low z-score is equal to -1.644853626
\n" ); document.write( "critical high z-score is equal to 1.644853626 \r
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\n" ); document.write( "\n" ); document.write( "to find the low raw score, you use z=(x-m)/s which becomes -1.644853626 = (x-.48)/.0353270435.
\n" ); document.write( "solve for x to get x = z*s+m which becomes x = -1.644853626 * .0353270435 + .48 which becomes x = .4218921845.\r
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\n" ); document.write( "\n" ); document.write( "to find the high raw score, you use z=(x-m)/s which becomes 1.644853626 = ((x-.48)/.0353270435.
\n" ); document.write( "solve for x to get x = 1*s+m which becomes x = 1.644853624 * .0353270435 + .48 which becomes x = .5381078155.\r
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\n" ); document.write( "\n" ); document.write( "your 90% confident estimate of the population proportion is equal to anywhere between .4218921845 and .5381078155.\r
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\n" ); document.write( "\n" ); document.write( "you would round as required.\r
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\n" ); document.write( "\n" ); document.write( "visually this would look like the following.\r
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\n" ); document.write( "\n" ); document.write( "first with z-scores\r
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\n" ); document.write( "\n" ); document.write( "next with raw scores\r
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\n" ); document.write( "\n" ); document.write( "the area shown at the bottom of each display is your confidence level which is equal to .9 = 90%.\r
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