document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=101144>Question 101144</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780073268620/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I'm having a problem solving the following equation - please help\r<BR>\n" );
document.write( "\n" );
document.write( "2/3k - (k+1/4) = 1/12(k+4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73623 by </B><A HREF=/tutors/aboutme.mpl?userid=mizzmake2><B>mizzmake2(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mizzmake2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73623\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2/3k-(k+1/4)=1/12(k+4)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "combine like terms and use the properties to get the variable on one side of the equals sign and the numbers on the other side. Remember to follow the order of operations.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(-1) (k + 1/4) + 2/3 k = 1/12 (k + 4)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "multiply -1 times k + 1/4;\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(-1) k - 1/4 + 2/3 k = 1/12 (k + 4)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "multiply 1/12 times k+4;\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(-1) k - 1/4 + 2/3 k = 1/12 k + 1/3\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "multiply -k to 2k/3;\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(-1/3) k - 1/4 = 1/12 k + 1/3\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "add 1/4 to both sides of the equation; \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(-1/3) k = 1/12 k + 7/12\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "subtract k from both sides of the equation;\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(-5/12) k = 7/12\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Divide both sides of the equation by -5/12, which is the same as multiplying both sides by the reciprocal of the fraction k = -7/5\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "So our solution is:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "k= -7/5<BR>\n" );
document.write( " = -1.4\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Good Luck!\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );