document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120535>Question 1120535</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A combined total of $48,000 is invested in two bonds that pay 3% and 7.5% simple interest. The annual interest is $2,880.00. How much is invested in each bond?  </SPAN>\n" );
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document.write( "By the traditional algebraic method....<br><BR>\n" );
document.write( "Let x = amount invested at 3%<BR>\n" );
document.write( "then 48000-x = amount invested at 7.5%<br><BR>\n" );
document.write( "The total interest is 2880:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.03%28x%29%2B.075%2848000-x%29+=+2880 ALIGN=MIDDLE  ALT=\".03%28x%29%2B.075%2848000-x%29+=+2880\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "Solving that equation (I leave it to you) gives the amount x invested at 3%.<br><BR>\n" );
document.write( "The fast, easy way to solve \"mixture\" problems like this that involve two \"ingredients\"....<br><BR>\n" );
document.write( "(1) The total yield on the investment is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2880%2F48000+=+0.06 ALIGN=MIDDLE  ALT=\"2880%2F48000+=+0.06\"   DISABLED_style= \"max-width:90%; height:auto;\" > or 6%.<BR>\n" );
document.write( "(2) The average return of 6% is 2/3 of the way from the lower rate of 3% to the higher rate of 7.5%:  (6-3)/(7.5-3) = 3/4.5 = 2/3.<BR>\n" );
document.write( "(3) Therefore 2/3 of the $48,000 (= $32,000) must have been invested at the higher rate.<br><BR>\n" );
document.write( "Answer: $16,000 at 3%, $32,000 at 7.5%. </SPAN>\n" );
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