document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120543>Question 1120543</A>: <I><SPAN STYLE=\"word-break: break-all;\"> After going to a fast food restaurant, customers are asked to take a survey. Out of a random sample of 340 customers, 290 said their experience was “satisfactory.” Let p represent the proportion of all customers who would say their experience was “satisfactory.”\r<BR>\n" );
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document.write( "A) What is the point estimate for p?<BR>\n" );
document.write( "B) Construct a 99% confidence interval for p.<BR>\n" );
document.write( "C) Give brief interpretation of this interval. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #736210 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=736210\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Point estimate is the results 290/340 or 0.8529<BR>\n" );
document.write( "99% CI ls mean +/- z0.995* sqrt (p*(1-p)/n)<BR>\n" );
document.write( "The interval is 2.576*sqrt(0.8529*0.1471/340); sqrt term is 0.0192<BR>\n" );
document.write( "The CI is 0.8529-0.0495, 0.8529+0.0495 or (0.8034, 0.9024)<BR>\n" );
document.write( "We don't know the true proportion of customers, but we are extremely confident it lies in the above interval. </SPAN>\n" );
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