document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120544>Question 1120544</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A catering service offers<BR>\n" );
document.write( "6 appetizers,<BR>\n" );
document.write( "4 main courses, and<BR>\n" );
document.write( "8 desserts. A customer is to select<BR>\n" );
document.write( "2 appetizers,<BR>\n" );
document.write( "3 main courses, and<BR>\n" );
document.write( "3 desserts for a banquet. In how many ways can this be done?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #736209 by </B><A HREF=/tutors/aboutme.mpl?userid=Shin123><B>Shin123(626)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Shin123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Shin123><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=736209\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 6C2+4C3+8C3 ways. There are 15+4+56=75 ways. </SPAN>\n" );
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