document.write( "Question 1120524: An object is propelled vertically upward with an initial velocity of 20 m/s. The distance s (in meters) of the object from the ground after t seconds is given by \"+s%28t%29+=+-4.9t%5E2+%2B+20t+\". When will the object be 15 meters above the ground? \n" ); document.write( "
Algebra.Com's Answer #736191 by Alan3354(69443)\"\" \"About 
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\"+s%28t%29+=+-4.9t%5E2+%2B+20t+\". When will the object be 15 meters above the ground?
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\n" ); document.write( "when s(t) = 20
\n" ); document.write( "\"20+=+-4.9t%5E2+%2B+20t+\"\r
\n" ); document.write( "\n" ); document.write( "\"4.9t%5E2+-+20t+%2B+20+=+0+\"
\n" ); document.write( "Solve for t.
\n" ); document.write( "You get 2 times, ascending & descending.
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\n" ); document.write( "Ooooh, 15, not 20.
\n" ); document.write( "The method is the same.
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\n" ); document.write( "If you solve for s(t) = 100, eg, you don't get a real number solution because the projectile never gets to 100 meters.
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