document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120515>Question 1120515</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A town under siege has sufficient food for 200 days at a constant rate of consumption. After 50 days, a quarter of the inhabitants escape and those left are put on half rations. How many days altogether will the remaining food last? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #736179 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=736179\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A town under siege has sufficient food for 200 days at a constant rate of consumption.<BR>\n" );
document.write( " After 50 days, a quarter of the inhabitants escape and those left are put on half rations.<BR>\n" );
document.write( " How many days altogether will the remaining food last?<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Lets do this assuming their are 100 people in the town originally<BR>\n" );
document.write( "Therefore we have: 100 * 200 = 20000 man-days of food available<BR>\n" );
document.write( "In 50 days, 100*50 = 5000 man-days have been consumed leaving 15000 man/days<BR>\n" );
document.write( "Now we have 75 people and 15000 man/days available<BR>\n" );
document.write( "It will take 15000/75 = 200 days to consume the food at full rations<BR>\n" );
document.write( "However at half rations it will last 400 days <BR>\n" );
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