document.write( "Question 1120469: using double angle formula
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\n" ); document.write( "a) sin^ 2 2x( cot^2 x-tan^2 x)= 4cos 2x\r
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Algebra.Com's Answer #736144 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Not complicated at all, actually.\r
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\n" ); document.write( "\n" ); document.write( "Double angle formula for sine:\r
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\n" ); document.write( "\n" ); document.write( "tangent is sine over cosine and cotangent is the reciprocal of tangent:\r
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\n" ); document.write( "\n" ); document.write( "Apply common denominator:\r
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\n" ); document.write( "\n" ); document.write( "Square the first factor:\r
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\n" ); document.write( "\n" ); document.write( "Eliminate factors common to numerator and denominator:\r
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\n" ); document.write( "\n" ); document.write( "Apply double angle identity for cosine:\r
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\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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