document.write( "Question 1120470: in a survey of women in a certain country (ages 20minus29), the mean height was 63.7 inches with a standard deviation of 2.73 inches. Answer the following questions about the specified normal distribution.
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document.write( "(a) What height represents the 95th percentile?
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document.write( "(b) What height represents the first quartile? \n" );
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Algebra.Com's Answer #736133 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! a) z-score for the 95% is 1.64 \n" ); document.write( ": \n" ); document.write( "1.64 = ( X - 63.7 ) / 2.73 \n" ); document.write( ": \n" ); document.write( "X - 63.7 = 1.64 * 2.73 = 4.4772 \n" ); document.write( ": \n" ); document.write( "X = 63.7 + 4.4772 = 68.1772 approximately 68.2 inches \n" ); document.write( ": \n" ); document.write( "b) z-score for 25% is -0.68 \n" ); document.write( ": \n" ); document.write( "-0.68 = ( X - 63.7 ) / 2.73 \n" ); document.write( ": \n" ); document.write( "X - 63.7 = -0.68 * 2.73 = -1.8564 \n" ); document.write( ": \n" ); document.write( "X = 63.7 - 1.85664 = 61.8436 approximately 61.8 inches \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |