document.write( "Question 1120446: When Juanita is as old as her mother is now, she will be five times as old as her son is now. By then, Juanita's son will be 8 years older than Juanita is now. Juanitas age combined with her mothers age, equals 100 years. how old is Juanita's son? \n" ); document.write( "
Algebra.Com's Answer #736110 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The other tutor didn't show a complete solution, so I don't know how much work remained to reach the answer from where they left off. In any case, I get a different answer than they did....

\n" ); document.write( "There are many different ways the problem can be set up; the method I used shown below may not be the easiest or most efficient....

\n" ); document.write( "Let m be the mother's current age

\n" ); document.write( "Then 100-m is Juanita's current age, since the sum of their ages is 100.

\n" ); document.write( "Let s be the son's current age.

\n" ); document.write( "The number of years until Juanita is her mother's current age is the difference of their current ages: m-(100-m) = 2m-100.

\n" ); document.write( "According to the statement of the problem, m is Juanita's age \"then\".

\n" ); document.write( "The son's age \"then\" is s + (2m-100).

\n" ); document.write( "Juanita \"then\" will be 5 times as old as her son is now:
\n" ); document.write( "(1) m = 5s.

\n" ); document.write( "Her son's age \"then\" will be 8 more than Juanita's current age:
\n" ); document.write( "(2) s+2m-100 = 108-m --> s+3m = 208.

\n" ); document.write( "Substitute (1) in (2) to find s, the son's current age.

\n" ); document.write( "s+3(5s) = 208
\n" ); document.write( "s+15s = 208
\n" ); document.write( "16s = 208
\n" ); document.write( "s = 13

\n" ); document.write( "The son's current age is 13.
\n" ); document.write( "So the mother's current age is 5(13) = 65.
\n" ); document.write( "So Juanita's current age is 100-65 = 35.
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