document.write( "Question 1120446: When Juanita is as old as her mother is now, she will be five times as old as her son is now. By then, Juanita's son will be 8 years older than Juanita is now. Juanitas age combined with her mothers age, equals 100 years. how old is Juanita's son? \n" ); document.write( "
Algebra.Com's Answer #736110 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The other tutor didn't show a complete solution, so I don't know how much work remained to reach the answer from where they left off. In any case, I get a different answer than they did.... \n" ); document.write( "There are many different ways the problem can be set up; the method I used shown below may not be the easiest or most efficient.... \n" ); document.write( "Let m be the mother's current age \n" ); document.write( "Then 100-m is Juanita's current age, since the sum of their ages is 100. \n" ); document.write( "Let s be the son's current age. \n" ); document.write( "The number of years until Juanita is her mother's current age is the difference of their current ages: m-(100-m) = 2m-100. \n" ); document.write( "According to the statement of the problem, m is Juanita's age \"then\". \n" ); document.write( "The son's age \"then\" is s + (2m-100). \n" ); document.write( "Juanita \"then\" will be 5 times as old as her son is now: \n" ); document.write( "(1) m = 5s. \n" ); document.write( "Her son's age \"then\" will be 8 more than Juanita's current age: \n" ); document.write( "(2) s+2m-100 = 108-m --> s+3m = 208. \n" ); document.write( "Substitute (1) in (2) to find s, the son's current age. \n" ); document.write( "s+3(5s) = 208 \n" ); document.write( "s+15s = 208 \n" ); document.write( "16s = 208 \n" ); document.write( "s = 13 \n" ); document.write( "The son's current age is 13. \n" ); document.write( "So the mother's current age is 5(13) = 65. \n" ); document.write( "So Juanita's current age is 100-65 = 35. \n" ); document.write( " |