document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120355>Question 1120355</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the HCF of two numbers is 6 and their lowest common multiple is 120.if one of the numbers is 30.find the other number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #736054 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=736054\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "For any two numbers, the product of the HCF and LCM of the two numbers is equal to the product of the two numbers.  So in this problem if the other number is x then<br><BR>\n" );
document.write( "6*120 = 30*x<BR>\n" );
document.write( "720 = 30x<BR>\n" );
document.write( "x = 720/30 = 24<br><BR>\n" );
document.write( "The other number is 24. </SPAN>\n" );
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