document.write( "Question 1120354: solve the equation and show the check of your solutions:
\n" ); document.write( "3x over x-4 minus 6 over x^2-7x+12 equal 2x over x-3\r
\n" ); document.write( "\n" ); document.write( "3x/x-4 - 6/x^2-7x+12 = 2x/x-3
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Algebra.Com's Answer #736029 by Boreal(15235)\"\" \"About 
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\n" ); document.write( "3x/x-4 - 6/x^2-7x+12 = 2x/x-3
\n" ); document.write( "note that x^2-7x+12 is also (x-4)(x-3)
\n" ); document.write( "multiply both sides by x^2-7x+12
\n" ); document.write( "this becomes
\n" ); document.write( "3x(x-3)-6=2x(x-4)
\n" ); document.write( "3x^2-9x-6=2x^2-8x
\n" ); document.write( "x^2-x-6=0
\n" ); document.write( "(x-3)(x+2)=0
\n" ); document.write( "x=3 and -2
\n" ); document.write( "x=3 is extraneous, because two terms will have 0 in the denominator.
\n" ); document.write( "x=-2 is the solution\r
\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "-6/-6 minus 6/30=-4/-5
\n" ); document.write( "1-0.2=0.8 checks.
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