document.write( "Question 1120354: solve the equation and show the check of your solutions:
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document.write( "3x over x-4 minus 6 over x^2-7x+12 equal 2x over x-3\r
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document.write( "3x/x-4 - 6/x^2-7x+12 = 2x/x-3 \n" );
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Algebra.Com's Answer #736029 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "3x/x-4 - 6/x^2-7x+12 = 2x/x-3 \n" ); document.write( "note that x^2-7x+12 is also (x-4)(x-3) \n" ); document.write( "multiply both sides by x^2-7x+12 \n" ); document.write( "this becomes \n" ); document.write( "3x(x-3)-6=2x(x-4) \n" ); document.write( "3x^2-9x-6=2x^2-8x \n" ); document.write( "x^2-x-6=0 \n" ); document.write( "(x-3)(x+2)=0 \n" ); document.write( "x=3 and -2 \n" ); document.write( "x=3 is extraneous, because two terms will have 0 in the denominator. \n" ); document.write( "x=-2 is the solution\r \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "-6/-6 minus 6/30=-4/-5 \n" ); document.write( "1-0.2=0.8 checks. \n" ); document.write( " |