document.write( "Question 1120240: In triangle WXY, WY=24m and angle Y=90degree. P lies on WX such that YP is perpendicular to WX, WP=18m and PX=14m. Q lies on YX such that QX=9.8m. Find
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document.write( "I) the length of YQ
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document.write( "ii) the area of triangle XPY \n" );
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Algebra.Com's Answer #735983 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Triangles XPY and XYW are similar, because they are both right triangles that share angle X. So \n" ); document.write( "PX/XY = XY/WX \n" ); document.write( "(XY)^2 = PX*WX = 14*32 = 448 \n" ); document.write( "XY = sqrt(448) = 8*sqrt(7) \n" ); document.write( "Then from the Pythagorean Theorem in triangle XPY, YP = 6*sqrt(7). \n" ); document.write( "Answers... \n" ); document.write( "(I) YQ = XY-XQ = 6*sqrt(7)-9.8 \n" ); document.write( "(II) the area of triangle XPY is (1/2)(PX)(PY) = (1/2)(14)(6*sqrt(7) = 42*sqrt(7) \n" ); document.write( " |