document.write( "Question 1120311: DURING A MANUFACTURING PROCESS A METAL PART IN A MACHINE IS EXPOSED TO VARYING TEMPERATURE CONDITION.THE MANUFACTURER OF THE MACHINE RECOMMENDS THAT THE TEMPERATURE OF THE MACHINE PART REMAIN BELOW 135F. THE TEMPERATURE,T IN DEGREE FAHRENHEIT X MINUTES AFTER THE MACHINE IS PUT INTO OPERATION IS MODELED BY THE EQUATION. T=-0.005X SQUARE + 0.45x + 125.\r
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document.write( "a. Tell whether the temperature of the part will ever reach or exceed 135 Fahrenheit. Using discriminant quadratic equation
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document.write( "b. If the machine is in operation for 90 minutes before being turned off, how many will the temperature of the part be 134 fahrenheit \n" );
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Algebra.Com's Answer #735972 by Theo(13342) You can put this solution on YOUR website! the equation is T = -0.005 * x^2 + .45 * x + 125.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the equation is in standard form of ax^2 + bx + c\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a = -.005 \n" ); document.write( "b = .45 \n" ); document.write( "c = 125\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the maximum value of T is when x = -b/2a.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "that would be when x = -.45 / (2*-.005)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get x = -.45 / -.01\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get x = 45\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 45, T = -.005 * x^2 + .45 * x + 125 = 135.125 degrees.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "yes, the part will reach or exceed 135 degrees.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if the part is in operation for 90 minutes, the part will have reached 134 degrees two times.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can replace T with y and graph the equation of y = -.005 * x^2 + .45 * x + 125.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the graph looks like this:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "from the graph, you can see that the part will reach or exceeed 134 degrees when x = 30 through x = 60.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's a period of 30 minutes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "from the graph, you can also see that the maximum value of the temperature is 135 degrees.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the part will be 125 degrees when x = 0 and when x = 90, according to the formula.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the points at which the temperature reaches 134 degrees was found by taking the equation of y = -.005 * x^2 + .45 * x + 125 and replacing y with 134.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get 134 = -.005 * x^2 + .45 * x + 125.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 134 from both sides of this equation to get -.005 * x^2 + .45 * x - 9 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factor this equation to get x = 30 or x = 60.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i used an online quadratic equation solver at https://www.mathsisfun.com/quadratic-equation-solver.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the results from that quadratic equation solver are shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if the quadratic equation solver is unavailable, you would solve using the quadratic formula.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that formula is referenced below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "http://www.purplemath.com/modules/quadform.htm\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |