document.write( "Question 1120283: x −2y ≥ 0, 2x−y ≤−2, x≥0,y ≥0 solve graphically \n" ); document.write( "
Algebra.Com's Answer #735961 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x-2y> =0 \n" ); document.write( "This is -2y>=-x or y <=(1/2)x \n" ); document.write( "The second is -y <=-2x-2 or y >=2x+2 \n" ); document.write( "For the first, which goes through the origin, y is BELOW the graph \n" ); document.write( "For the second, at (0, 0) is NOT a solution since 0 is not >=2, so the side AWAY from the origin is what is desired. \n" ); document.write( "What is desired is the sector that lies wholly in quadrant III. \n" ); document.write( " |