document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=101108>Question 101108</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 5m less than twice its width. If its width is increased by 5m and its length by 2m, the new area would be 81 sq m more than the original. Find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73595 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73595\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2w-5<BR>\n" );
document.write( "A=w(2w-5)<BR>\n" );
document.write( "(w+5)((2w-5)+2)=81+w(2w-5)<BR>\n" );
document.write( "(w+5)(2w-3)=81+2w^2-5w<BR>\n" );
document.write( "2w^2+7w-15=2w^2-5w+81<BR>\n" );
document.write( "12w=96<BR>\n" );
document.write( "w=8<BR>\n" );
document.write( "L=16-5=11<BR>\n" );
document.write( "I checked this and its ok.<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );