document.write( "Question 1120270: In the trapezoid CB=12, AB=30, CD=8 and angle B=30. What is the area? I should not use trigonometry to solve this problem. \n" ); document.write( "

Algebra.Com's Answer #735939 by ikleyn(52787) $\"\"$ $\"About$

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document.write( "I will assume that in a trapezoid ABCD the segments AB and DC are parallel bases of the length of 30 and 8 units, respectively..\r\n" );
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document.write( "The lateral side BC is 12 units long.\r\n" );
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document.write( "Since the angle B is of 30 degrees, the height of the trapezoid from the vertex C drawn to the base AB is half of the length BC.\r\n" );
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document.write( "Hence, the altitude of the trapezoid is 6 units long.\r\n" );
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document.write( "Next, the area of a trapezoid (of ANY trapezoid) is the product of the altitude size by half of the sum of its bases.\r\n" );
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document.write( "In your case, the area of the trapezoid is  A =  =  = 6*19 = 114 square units.\r\n" );
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