document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120242>Question 1120242</A>: <I><SPAN STYLE=\"word-break: break-all;\"> factorise x^2+4y^216z^2+4xy+16yz+8zx and find the value when x=2, y=-1 and z=1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #735907 by </B><A HREF=/tutors/aboutme.mpl?userid=Shin123><B>Shin123(626)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Shin123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Shin123><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=735907\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x<SUP>2</SUP>+4y<SUP>2</SUP>+16z<SUP>2</SUP>+4xy+16yz+8zx. First part, the equation factors to (x+2y+4z)<SUP>2</SUP> Next part, (x+2y+4z)<SUP>2</SUP>= (2+2(-1)+4(1))<SUP>2</SUP>=(2+(-2)+4)<SUP>2</SUP>=4<SUP>2</SUP>=16. </SPAN>\n" );
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