document.write( "Question 1120196: The product of the second and third of three consecutive integers is 2 more than 12 times the first number \n" ); document.write( "
Algebra.Com's Answer #735868 by Theo(13342)\"\" \"About 
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let x = the first number.\r
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\n" ); document.write( "\n" ); document.write( "since the numbers are consecutive, then your numbers are:\r
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\n" ); document.write( "\n" ); document.write( "x
\n" ); document.write( "x+1
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\n" ); document.write( "\n" ); document.write( "the product of the second and third numbers is equal to 2 plus 12 * the first number.\r
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\n" ); document.write( "\n" ); document.write( "the equation for this is (x + 1) * (x + 2) = 2 + 12 * x\r
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\n" ); document.write( "\n" ); document.write( "perform the multiplication on the left side of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 2x + x + 2 = 2 + 12x\r
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\n" ); document.write( "\n" ); document.write( "combine like terms to get:\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 3x + 2 = 2 + 12x\r
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\n" ); document.write( "\n" ); document.write( "subtract (2 + 12x) from both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 3x + 2 - (2 + 12x) = 0\r
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\n" ); document.write( "\n" ); document.write( "simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "x^2 + 3x + 2 - 2 - 12x = 0\r
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\n" ); document.write( "\n" ); document.write( "combine like terms to get:\r
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\n" ); document.write( "\n" ); document.write( "x^2 - 9x = 0\r
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\n" ); document.write( "\n" ); document.write( "factor to get:\r
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\n" ); document.write( "\n" ); document.write( "x * (x - 9) = 0\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get:\r
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\n" ); document.write( "\n" ); document.write( "x = 0 or x = 9\r
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\n" ); document.write( "\n" ); document.write( "the number could be 0 or it could be 9.\r
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\n" ); document.write( "\n" ); document.write( "when the number is 0, the sequence is 0,1,2.\r
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\n" ); document.write( "\n" ); document.write( "the product of the second and third number is 2.\r
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\n" ); document.write( "\n" ); document.write( "2 plus 12 * the first number is equal to 2 + 0 which is equal to 2.\r
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\n" ); document.write( "\n" ); document.write( "the product of the second and third number is equal to 2 plus 12 * the first number is confirmed to be true when the first number is equal to 0.\r
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\n" ); document.write( "\n" ); document.write( "when the number is 9, the sequence is 9,10,11\r
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\n" ); document.write( "\n" ); document.write( "the product of the second and third number is 10 * 11 = 110\r
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\n" ); document.write( "\n" ); document.write( "2 plus 12 times the first number is equal to 2 + 12 * 9 which is equal to 2 + 108 which is equal to 110.\r
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\n" ); document.write( "\n" ); document.write( "the product of the second and third number is equal to 2 plus 12 * the first number is confirmed to be true.\r
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\n" ); document.write( "\n" ); document.write( "looks like either 0 or 9 would be a correct solution.\r
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