document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120188>Question 1120188</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Kwan family purchased their house in 2010 for $100,000. If the value of real estate increases at a rate of 10% per year, how much would their house be worth in 2025? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #735865 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=735865\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f = p * (1 + r) ^ n\r<BR>\n" );
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document.write( "f is the future value<BR>\n" );
document.write( "p is the present value<BR>\n" );
document.write( "r is the interest rate per time period<BR>\n" );
document.write( "n is the number of time periods.\r<BR>\n" );
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document.write( "formula becomes:\r<BR>\n" );
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document.write( "f = 100,000 * (1 + .10) ^ (2025 - 2010)\r<BR>\n" );
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document.write( "simplify to get f = 100,000 * (1.10) ^ 15\r<BR>\n" );
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document.write( "solve for f go get f = 147,724.8169\r<BR>\n" );
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document.write( "that's what the house is worth in 15 years at 10% a year compounded annually.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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