document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1120183>Question 1120183</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Soybean meal is 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 11% protein? How many pounds of the cornmeal should be in the mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #735862 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=735862\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is a quick way to solve mixture problems like this involving must two ingredients.<br><BR>\n" );
document.write( "See if it makes sense to you....  You will get the answer in a fraction of the time required for the formal algebraic solution shown by the other tutors.<br><BR>\n" );
document.write( "(1) 11% is 3/8 of the way from 8% to 16%.<BR>\n" );
document.write( "(2) Therefore 3/8 of the mixture must be the 16% ingredient.<BR>\n" );
document.write( "Answer: 3/8 of the mixture -- 3/8 of 320 pounds = 120 pounds -- is the 16% protein soybean meal; the other 5/8 of the mixture -- the other 200 pounds -- is the 8% protein cornmeal. </SPAN>\n" );
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