document.write( "Question 1120190: a boy has 3 library tickets and 8 books of his interest in the library. of these 8, he does not want to borrow chemistry part 2, unless chemistry part 1 is also borrowed. in how many ways can he choose the three books to be borrowed? \n" ); document.write( "
Algebra.Com's Answer #735860 by greenestamps(13206) You can put this solution on YOUR website! \n" ); document.write( "He can choose either \n" ); document.write( "(1) chemistry part 1 and any 2 of the other 7 books: C(1,1)*C(7,2) = 1*21 = 21 \n" ); document.write( "or \n" ); document.write( "(2) not chemistry part 1, and therefore not chemistry part 2, and any 3 of the other 6 books: C(6,3) = 20 \n" ); document.write( "The total number of ways he can choose 3 books is 21+20 = 41. \n" ); document.write( " |