document.write( "Question 1120183: Soybean meal is 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 11% protein? How many pounds of the cornmeal should be in the mixture? \n" ); document.write( "
Algebra.Com's Answer #735857 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Soybean meal is 16% protein; cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 11% protein? How many pounds of the cornmeal should be in the mixture?
\n" ); document.write( "
Let the amount of protein in CORNMEAL be E
\n" ); document.write( "Then amount of protein in soybean = 320 - E
\n" ); document.write( "We then get: .08E + .16(320 - E) = .11(320)
\n" ); document.write( "Solve this for E, the amount of protein in cornmeal, which is what was asked for. \n" ); document.write( "
\n" );