document.write( "Question 1120164: A 50.0 g silver spoon at 20.0 0C is placed in a cup of coffee at 90.0 0C. How much heat will the cooler spoon absorb from the warmer coffee in order to reach a warmer temperature of 89 0C? \n" ); document.write( "

Algebra.Com's Answer #735820 by ikleyn(52802) $\"\"$ $\"About$

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document.write( "How much heat = 50*0.0558*(89-20) = 192.51 calories,    OR\r\n" );
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document.write( "              = 50*0.233*(89-20) = 803.85 joules.\r\n" );
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document.write( "Here 0.0558 = 0.0558 cal/(g*C) is the specific heat for silver,   also equal to\r\n" );
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document.write( "            = 0.233 J/(g*C)   in other dimension unit  (Joules instead of calories).\r\n" );
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document.write( "The general formula for absorbed heat is  H = M*c*dT,\r\n" );
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document.write( "where M is the mass, c is the specific heat capacity and dT is the temperature difference.\r\n" );
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