document.write( "Question 101094: Colin invested $37,000, part at 16% and part at 3%. If the total interest at the end of the year is $3,320, how much did he invest at 16%? \n" ); document.write( "
Algebra.Com's Answer #73581 by tutorcecilia(2152)\"\" \"About 
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Let x+y=37,000
\n" ); document.write( "Than y=37,000-x
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\n" ); document.write( ".16x + .03y = 3,320
\n" ); document.write( "So, .16x + .03(37,000-x)=3,320 [substitute y=37,000-x in the equation]
\n" ); document.write( ".16x + 1110- .03x=3,320 [sovle for the x-term]
\n" ); document.write( ".16x-.03x=3,320-1110
\n" ); document.write( ".13x=2210
\n" ); document.write( ".13x/.13=2210/.13
\n" ); document.write( "x=$17,000 invested at 16%
\n" ); document.write( ".
\n" ); document.write( "y=37,000-x
\n" ); document.write( "y=37,000-17,000=20,000\r
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\n" ); document.write( "Check by plugging all of the values back into the original equation and solve:
\n" ); document.write( ".16x + .03y = 3,320
\n" ); document.write( " .16(17,000) + .03(20,000) = 3,320
\n" ); document.write( "2720+600=3320
\n" ); document.write( "3320=3320\r
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