document.write( "Question 101094: Colin invested $37,000, part at 16% and part at 3%. If the total interest at the end of the year is $3,320, how much did he invest at 16%? \n" ); document.write( "
Algebra.Com's Answer #73580 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .16X+.03(37,000-X)=3,320 \n" ); document.write( ".16X+1,110-.03X)=3,320 \n" ); document.write( ".16X-.03X=3,320-1,110 \n" ); document.write( ".13X=2,210 \n" ); document.write( "X=2,210/.13 \n" ); document.write( "X=17,000 INVESTED @16%. \n" ); document.write( "37,000-17,000=20,000 INVESTED @ 3%. \n" ); document.write( "PROOF \n" ); document.write( ".16*17,000+.03*20,000=3,320 \n" ); document.write( "2720+600=3,320 \n" ); document.write( "3,320=3,320 \n" ); document.write( " \n" ); document.write( " |