document.write( "Question 101094: Colin invested $37,000, part at 16% and part at 3%. If the total interest at the end of the year is $3,320, how much did he invest at 16%? \n" ); document.write( "
Algebra.Com's Answer #73580 by checkley71(8403)\"\" \"About 
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.16X+.03(37,000-X)=3,320
\n" ); document.write( ".16X+1,110-.03X)=3,320
\n" ); document.write( ".16X-.03X=3,320-1,110
\n" ); document.write( ".13X=2,210
\n" ); document.write( "X=2,210/.13
\n" ); document.write( "X=17,000 INVESTED @16%.
\n" ); document.write( "37,000-17,000=20,000 INVESTED @ 3%.
\n" ); document.write( "PROOF
\n" ); document.write( ".16*17,000+.03*20,000=3,320
\n" ); document.write( "2720+600=3,320
\n" ); document.write( "3,320=3,320
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