document.write( "Question 1120123: A hemispherical bowl of diameter 14cm mounted on a bucket in the form of a frustum of a cone. If the base diameter of the bucket is 7cm and the total height of the figure is 21cm, calculate the total surface area of the figure. (Take pi = 22/7). \n" ); document.write( "

Algebra.Com's Answer #735790 by ikleyn(52790) $\"\"$ $\"About$

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document.write( "1.  Base radius of the frustum cone is  r = 3.5 cm.\r\n" );
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document.write( "    The upper radius of the frustum cone is  R = 7 cm.\r\n" );
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document.write( "    The height of the frustum of the cone is  h = 21 - 7 = 14 cm.\r\n" );
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document.write( "    The slant height of the frustum of the cone is  s =  =  = 14.43 cm  (approximately).\r\n" );
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document.write( "2.  The latent surface of the frustum of the cone is  \r\n" );
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document.write( "     =  =  = 476.19 square centimeters.\r\n" );
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document.write( "       (regarding this general formula see the link http://mathworld.wolfram.com/ConicalFrustum.html )\r\n" );
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document.write( "3.  The surface area of the semi-sphere is   =  =  = 308 square centimeters.\r\n" );
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document.write( "4.  The area of the base is   =  =  = 38.5 square centimeters.\r\n" );
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document.write( "5.  The answer to the problem question is the sum  \r\n" );
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document.write( "     +  +  = 476.19 + 308 + 38.5 = 822.69 square centimeters.\r\n" );
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