document.write( "Question 1120098: Pls solve the following algebraic equations; 1. A man walks for 2 hrs at 6 km/h. He then cycled for a certain speed at16km/h. If he travelled 36 km altogether, for how many hours did he cycle? 2. A sum of #244 is made up of 10-naira notes and 1-naira coins. There are six times as many naira notes as there are naira coins. Find the number of 10-naira notes. 3. Anna has#30 and Ojo has#186. If Anna saves #5 a day and Ojo spends #7 day, after how many days will they have equal amounts? \n" ); document.write( "
Algebra.Com's Answer #735762 by htmentor(1343)\"\" \"About 
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1. Distance walked = 6 km/h * 2 h = 12 km
\n" ); document.write( "Distance cycled = 36 - 12 = 24 km
\n" ); document.write( "The time cycled = 24 km/(16 km/h) = 1.5 h\r
\n" ); document.write( "\n" ); document.write( "2. Let x = the number of coins. Thus the number of notes = 6x
\n" ); document.write( "The total amount = 244 = 6x*10 + x = 61x
\n" ); document.write( "Thus x = 4
\n" ); document.write( "The number of coins = 4, number of notes = 24\r
\n" ); document.write( "\n" ); document.write( "3. Let d = the number of days
\n" ); document.write( " Anna's amount = 30 + 5d
\n" ); document.write( " Ojo's amount = 186 - 7d
\n" ); document.write( "Set the two amounts equal:
\n" ); document.write( "30 + 5d = 186 - 7d
\n" ); document.write( "Solving for d, we get 12d = 156 -> d = 13
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