document.write( "Question 1120055: Use graphical approximation techniques or an equation solver to approximate the desired interest rate. A person makes annual payments of $ 1000 into an ordinary annuity. At the end of 5 years, the amount in the annuity is $ 5703.88. What annual nominal compounding rate has this annuity earned? \n" ); document.write( "
Algebra.Com's Answer #735729 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A person makes annual payments of $ 1000 into an ordinary annuity. \n" ); document.write( " At the end of 5 years, the amount in the annuity is $ 5703.88. \n" ); document.write( " What annual nominal compounding rate has this annuity earned? \n" ); document.write( ": \n" ); document.write( "We can use the annuity formula \n" ); document.write( "P( \n" ); document.write( "P =payment \n" ); document.write( "i = interest rate \n" ); document.write( "t = periods \n" ); document.write( "Fv = Final value \n" ); document.write( ": \n" ); document.write( "1000( \n" ); document.write( "Put in the form that we can graph; i = x \n" ); document.write( "1000( \n" ); document.write( "divide both sides by 1000 \n" ); document.write( " \n" ); document.write( "Approx solution; x = .066 or 6.6% interest \n" ); document.write( " \n" ); document.write( "multiply both sides by x \n" ); document.write( "(1+x)^5 - 1 = 5.704x \n" ); document.write( "A quadratic equation we can graph \n" ); document.write( "(1+x)^5 - 5.704x - 1 = 0 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |