document.write( "Question 1120049: The sum of the square of three consecutive odd integers is 371. Find the odd integers\r
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Algebra.Com's Answer #735703 by math_helper(2461)\"\" \"About 
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\"n%5E2+%2B+%28n%2B2%29%5E2+%2B+%28n%2B4%29%5E2+=+371+\"
\n" ); document.write( "\"+n%5E2+%2B+%28n%5E2%2B4n%2B4%29+%2B+%28n%5E2%2B8n%2B16%29+=+371+\"
\n" ); document.write( "\"+3n%5E2+%2B+12n+-+351+=+0+\"
\n" ); document.write( "\"+n%5E2+%2B+4n+-+117+=+0+\"
\n" ); document.write( "\"+%28n%2B13%29%28n-9%29+=+0+\"\r
\n" ); document.write( "\n" ); document.write( "n=9 and or n=-13\r
\n" ); document.write( "\n" ); document.write( "n=9: integers are 9,11,13 \r
\n" ); document.write( "\n" ); document.write( "Check: \"+9%5E2+%2B+11%5E2+%2B+13%5E2+=+81%2B121%2B169+=+371+\"\r
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\n" ); document.write( "and
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\n" ); document.write( "\n" ); document.write( "覧覧覧覧覧覧覧覧予r
\n" ); document.write( "\n" ); document.write( "Tutor MathTherapy showed this method, which is a bit quicker, and perhaps less error-prone :\r
\n" ); document.write( "\n" ); document.write( "Let n = the middle integer
\n" ); document.write( "n-2 = smaller
\n" ); document.write( "n+2 = larger\r
\n" ); document.write( "\n" ); document.write( "\"+%28n-2%29%5E2+%2B+%28n%5E2%29+%2B+%28n%2B2%29%5E2+=+371+\"
\n" ); document.write( "\"++%28n%5E2-4n%2B4%29+%2B+n%5E2+%2B+%28n%5E2%2B4n%2B4%29+=+371+\"
\n" ); document.write( "\"++3n%5E2+-+363+=+0+\"
\n" ); document.write( "\"++n%5E2+-+121+=+0+\"
\n" ); document.write( "\"+%28n-11%29%28n%2B11%29+=+0+\"\r
\n" ); document.write( "\n" ); document.write( "n = 11 and/or n=-11 which gives the same solutions (9,11,13) and (-13,-11,-9). \r
\n" ); document.write( "\n" ); document.write( "覧覧覧覧\r
\n" ); document.write( "\n" ); document.write( "Very good method tutor Alan3354! Thanks.
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