document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1119974>Question 1119974</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am sorry I know this is a lengthy question but I am just not sure what the answers are. \r<BR>\n" );
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document.write( "f(x)=1/4x^3+4x2-x\r<BR>\n" );
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document.write( "i. What are the end behaviours of this type of function (what quadrant does it begin and end in?)<BR>\n" );
document.write( "ii. What is the maximum and minimum number of x-intercepts for this type of function?<BR>\n" );
document.write( "iii. What is the maximum and minimum number of turns for this type of function?<BR>\n" );
document.write( "iv. State if there are any restrictions on the domain and range on this type of function.\r<BR>\n" );
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document.write( "Any help to any of these questions would be so helpful thank you so much in advance.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #735613 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=735613\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It is a cubic so x at -oo it is -oo  and x at + oo is +oo.  The only term that matters at end behavior is the term with the largest exponent.\r<BR>\n" );
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document.write( "The number of sign changes are 1, so it can have one positive root.<BR>\n" );
document.write( "Change the signs and it is -(1/4)x^3+4x^2+x. It can have one negative root.<BR>\n" );
document.write( "The third root must be 0.<BR>\n" );
document.write( "This means 2 turns.<BR>\n" );
document.write( "There are no restrictions on either the domain or range of the function, since one is not dividing by 0 anywhere.\r<BR>\n" );
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