document.write( "Question 1119963: Based on a sample of 45 people, the sample mean GPA was 3.36 with a standard deviation of 0.02\r
\n" ); document.write( "\n" ); document.write( "The p-value is:
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Algebra.Com's Answer #735588 by Boreal(15235)\"\" \"About 
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To compute a p-value, one needs to know what the value of the sample should be compared to, some hypothesized or presumed value. It is possible to compute the standard error from the above but not the difference in GPAs, since only one is given.
\n" ); document.write( "Ho:GPA is 3.40
\n" ); document.write( "Ha: GPA is not 3.40
\n" ); document.write( "alpha=0.10
\n" ); document.write( "test stat t=0.95, 2 way, df=44
\n" ); document.write( "Critical value |t|>1.68
\n" ); document.write( "t=mean diff/s/sqrt (n)=-0.04/(0.02/sqrt(45))=-13.42
\n" ); document.write( "highly significant p-value <0.0001
\n" ); document.write( "(Could it be possible that the standard deviation of the sample was 0.2?)
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