document.write( "Question 1119944: A collection of nickels, dimes, and quarters consist of
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Algebra.Com's Answer #735586 by ikleyn(52788) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "It is typical one-unknown problem.\r\n" );
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document.write( "Let x be the number of quarters.\r\n" );
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document.write( "Then the number of dimes is 2x, according to the condition.\r\n" );
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document.write( "Then the number of nickels must be (95-(x+2x)) = (95-3x).\r\n" );
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document.write( "The money equation is\r\n" );
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document.write( "   5*(95-3x) + 10*(2x) + 25*x = 1075 cents.\r\n" );
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document.write( "Simplify and solve for x:\r\n" );
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document.write( "    5*95 - 15x + 20x + 25x = 1075\r\n" );
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document.write( "    30x = 1075 - 5*95 \r\n" );
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document.write( "    30x = 600  ====>  x =  = 20.\r\n" );
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document.write( "Answer.  20 quarters,  2*20 = 40 dimes and  (95 - 20 - 40) = 35 nickels.\r\n" );
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