document.write( "Question 1119939: An object is dropped from the top of ABC Tower, 1,500 feet from the ground. Calculate the average velocity of the object over the interval t=2 seconds and t=3 seconds. The position function of the projectile is s(t) = -16t2 + V0t + h0, where V0t is the initial velocity of the object and h0 is the height to which it is dropped.\r
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document.write( "Answers:\r
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document.write( "at t=2 seconds, s(t) = _____ feet\r
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document.write( "at t=3 seconds, s(t) = _____ feet\r
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document.write( "average velocity = _____ ft/sec\r
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Algebra.Com's Answer #735571 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! An object is dropped from the top of ABC Tower, 1,500 feet from the ground. Calculate the average velocity of the object over the interval t=2 seconds and t=3 seconds. The position function of the projectile is s(t) = -16t2 + V0t + h0, where V0t [sic] is the initial velocity of the object and h0 is the height to which it is dropped. \n" ); document.write( "Vo is the initial velocity, not Vo*t \n" ); document.write( "-------- \n" ); document.write( "Answers:\r \n" ); document.write( "\n" ); document.write( "at t=2 seconds, s(t) = _____ feet \n" ); document.write( "It's s(2) \n" ); document.write( "Sub 2 for t. \n" ); document.write( "==================== \n" ); document.write( "at t=3 seconds, s(t) = _____ feet \n" ); document.write( "Same as above, t = 3 \n" ); document.write( "========================= \n" ); document.write( "average velocity = _____ ft/sec \n" ); document.write( "= s(3) - s(2)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |