document.write( "Question 1119907: A rock is thrown upward with a speed of 48 feet per second from the edge of a cliff 400 feet above the ground. What is the speed of the rock when it hits the ground? Use acceleration due to gravity as -32 feet per second squared. \n" ); document.write( "
Algebra.Com's Answer #735550 by ikleyn(52788)\"\" \"About 
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document.write( "In Physics, the students solve this problem by applying the Energy Conservation  Law\r\n" );
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document.write( "\"%28m%2Av%5E2%29%2F2\" + \"m%2Ag%2AH\" = \"%28mV%5E2%29%2F2\",\r\n" );
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document.write( "where m is the mass of the body, v is the starting velocity (directed vertically up),  V = the final velocity directed \r\n" );
document.write( "vertically down (the value under the question) and g = 32 ft/s^2 given in the condition.\r\n" );
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document.write( "Canceling \"m\" in both sides and simplifying, you get\r\n" );
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document.write( "V = \"sqrt%28v%5E2+%2B+2%2Ag%2AH%29\" = \"sqrt%2848%5E2+%2B+2%2A32%2A400%29\",\r\n" );
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document.write( "and what you need to do is to use your calculator.\r\n" );
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