document.write( "Question 1119888: Please help me solve this of simple way. Thank. You\r
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document.write( "Three coins are tossed. Find the probability of tossing each of the following events:
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document.write( "1. Three heads.
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document.write( "Answer:
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document.write( "2. Two heads and a tail.
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document.write( "3. At least one tail.
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document.write( "4. At least two heads.
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Algebra.Com's Answer #735527 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Three heads is (1/2)(1/2)(1/2) or 1/8 \n" ); document.write( "Two heads and a tail can occur 3 different ways, HHT HTH THH, so its probability is 3/8. \n" ); document.write( "At least one tail is 1-no tails, which is 1-(1/8)=7/8 \n" ); document.write( "At least two heads is two heads (3/8 probability from above) and three heads, which is probability 1/8. The sum is 1/2. \n" ); document.write( " |