document.write( "Question 1119884: A ball is dropped from a height of 20.0 ft. above the ground
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Algebra.Com's Answer #735526 by ikleyn(52847) $\"\"$ $\"About$

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document.write( "    The initial potential energy was P = m*g*h,   \r\n" );
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document.write( "    where m is the mass, g = 32 ft/s^2 is the gravity acceleration and h = 20 ft.\r\n" );
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document.write( "    When the falling body reaches the height of 10 meters above the ground, its potential energy will be half\r\n" );
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document.write( "    of the original potential energy.\r\n" );
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document.write( "    The other half of the initial potential energy will transform to the kinetic energy of the falling body.\r\n" );
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document.write( "    Hence, at the the height of 10 meters above the ground, the body will have equal amounts of its potential and kinetic energy.\r\n" );
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document.write( "    It gives the Answer to the problem question:\r\n" );
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document.write( "        At the height of 10 meters above the ground, the body will have equal amounts of potential and kinetic energy.\r\n" );
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document.write( "        Its total energy remains the same, but now the half of the energy is potential, while the another half is kinetic.\r\n" );
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document.write( "     =   ====>   = 2*g*h  ====>  V =  =  =  = 35.78 ft/s.\r\n" );
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