document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1119851>Question 1119851</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Im not quite understanding this question also. x^(5/2)&#8722;12x^(5/4)+36=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #735480 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=735480\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%28v=x%5E%285%2F4%29%2Cv%5E2=%28x%5E%285%2F4%29%29%5E2=x%5E%282%285%2F4%29%29=x%5E%285%2F2%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=v%5E2-12v%2B36=0 ALIGN=MIDDLE  ALT=\"v%5E2-12v%2B36=0\"   DISABLED_style= \"max-width:90%; height:auto;\" >, which might be much easier; solve and then back-substitute.  Solve that then. </SPAN>\n" );
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